4x^2=57(.1-x)(.25-x)

Solution for 4x^2=57(.1-x)(.25-x) equation:

4x^2=57(.1-x)(.25-x)

We move all terms to the left:

4x^2-(57(.1-x)(.25-x))=0

We add all the numbers together, and all the variables

4x^2-(57(-1x+0.1)(-1x+0.25))=0

We multiply parentheses ..

4x^2-(57(+x^2-0.25x-0.1x+0.025))=0


We calculate terms in parentheses: -(57(+x^2-0.25x-0.1x+0.025)), so:

57(+x^2-0.25x-0.1x+0.025)

We multiply parentheses

57x^2+0x+0x+1.425

We add all the numbers together, and all the variables

57x^2+2x+1.425

Back to the equation:

-(57x^2+2x+1.425)


We get rid of parentheses

4x^2-57x^2-2x-1.425=0

We add all the numbers together, and all the variables

-53x^2-2x-1.425=0

a = -53; b = -2; c = -1.425;
Δ = b2-4ac
Δ = -22-4·(-53)·(-1.425)
Δ = -298.1
Delta is less than zero, so there is no solution for the equation